How to compare two property files in two different folders using shell script
input can be path of the two folders?
There are multiple files in both folders and each files needs to be checked
You probably need to explain your requirements a bit more. However it's most likely you can do what you want with the diff command (with a little help from sort and/or grep).
Let's assume you have two files: a.properties and b.properties
If you simply want to know if the files are different in any way, you can use
diff a.properties b.properties
You'll get no output if they're identical or a list of differences.
If you want a comparison on a more semantic level, that is, are the two sets of properties identical, then you need to do a bit more. The files can differ textually, but mean the same thing to Java programs that use them. For example, the properties can occur in a different order. There can be blank lines, other whitespace and comments.
If this is the case, do you care if the comments are identical? They won't effect the operation of your program, but they have a meaning (and value to those reading the file). If you don't care, strip them out.
You probably don't care about blank lines as they have no meaning.
You also need to handle the following case:
a.properties: prop = value b.properties: prop=value
Again, different textually (note the spaces around the equals) but have the same meaning in Java.
Starting simple, let's assume the properties occur in the same order.
Ignore blank lines:
diff -B a.properties b.properties
Handle random white space (eg. around the equals sign)
diff -w a.properties b.properties
Combine all of this:
diff -w -B a.properties b.properties
Strip out comments:
grep -v '^#.*$' a.properties > a.tmp grep -v '^#.*$' b.properties > b.tmp diff -w -B a.tmp b.tmp rm a.tmp b.tmp
Allow for properties in a different order, strip comments:
grep -v '^#.*$' a.properties | sort > a.tmp grep -v '^#.*$' b.properties | sort > b.tmp diff -w -B a.tmp b.tmp rm a.tmp b.tmp