Leon Gaban Leon Gaban - 1 year ago 72
AngularJS Question

How to avoid escaping when trying to replace $location.search?

const createParam = (key, value) => '?'+key+'='+value;

const rebuildUrl = (linkUrl, params) => {

console.log('params', params);
_.each(params, (param)=> {
linkUrl += createParam(param.key, param.value);

console.log('linkUrl', linkUrl);
// window.location.href = linkUrl;

const checkForStoredLink = () => {
Util.notEmpty(storedLinkParams) ? rebuildUrl('', storedLinkParams) : null;

storedLinkParams = [
{ key: "ticker",
value: "AAPL" },
// etc...

My function above will take in the params array and generate a string like this:

My current URL looks like this:


And once my function above reaches the
line it ended up looking like this, which breaks the UI:


Answer Source

$location.search expects search parameters to be delimited by &. e.g.

$location.search('param1=value1&param2=value2'); results in: ?param1=value1&param2=value2

$location.search('?param1=value1?param2=value2') results in: ?%3Fparam1=value1%3Fparam2.

If you start using & to delimit the params then your life can be even simpler, you can pass in an object and avoid any string building:

$location.search(_.fromPairs(params, param => [param.key, param.value]));

Code above assumes the _ is a recent version of lodash.js, if not:

_.each(params, param => $location.search(param.key, param.value));

To answer the question in the title: If you really want to set raw urls yourself, then a solution to that could be to inject your own wrapper around window.location, but would not recommend

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