Danny Fox - 1 year ago 74

C# Question

I have a list which I need to sort into an order provided it contains ALL of the numbers in its sequence:

Manually just setting them does not seem like the way to go about it.

I know how to order lists to be ascending or descending but having the modulus 4 is sending my head funny.

Modulus of 4 is due to this being linked to node neighbours on a grid

I do not know what order they are put into the list initially as it is random and changes every time - Procedural generation of grid connections

I do not want a new list, I just want to simply re-arrange the current one.

List Count of 3:

0, 1, 2

1, 2, 3

2, 3, 0

3, 0, 1

`if (acceptedIndicies.Contains(0) && acceptedIndicies.Contains(1) && acceptedIndicies.Contains(2)) // Top-Right-Down`

{

// Order List in the sequence

acceptedIndicies[0] = 0;

acceptedIndicies[1] = 1;

acceptedIndicies[2] = 2;

}

else if (acceptedIndicies.Contains(1) && acceptedIndicies.Contains(2) && acceptedIndicies.Contains(3)) // Right-Down-Left

{

// Order List in the sequence

acceptedIndicies[0] = 1;

acceptedIndicies[1] = 2;

acceptedIndicies[2] = 3;

}

else if (acceptedIndicies.Contains(2) && acceptedIndicies.Contains(3) && acceptedIndicies.Contains(0)) // Down-Left-Top

{

// Order List in the sequence

acceptedIndicies[0] = 2;

acceptedIndicies[1] = 3;

acceptedIndicies[2] = 0;

}

else if (acceptedIndicies.Contains(3) && acceptedIndicies.Contains(0) && acceptedIndicies.Contains(1)) // Left-Top-Right

{

// Order List in the sequence

acceptedIndicies[0] = 3;

acceptedIndicies[1] = 0;

acceptedIndicies[2] = 1;

}

List Count of 2:

0, 1

1, 2

2, 3

3, 0

`if (acceptedIndicies.Contains(0) && acceptedIndicies.Contains(1))`

{

// Order List in the sequence

acceptedIndicies[0] = 0;

acceptedIndicies[1] = 1;

}

else if (acceptedIndicies.Contains(1) && acceptedIndicies.Contains(2))

{

// Order List in the sequence

acceptedIndicies[0] = 1;

acceptedIndicies[1] = 2;

}

else if (acceptedIndicies.Contains(2) && acceptedIndicies.Contains(3))

{

// Order List in the sequence

acceptedIndicies[0] = 2;

acceptedIndicies[1] = 3;

}

else if (acceptedIndicies.Contains(3) && acceptedIndicies.Contains(0))

{

// Order List in the sequence

acceptedIndicies[0] = 3;

acceptedIndicies[1] = 0;

}

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

You can do the following:

Build the valid modulus sequence. That's easy:

`var modulusSequence = Enumerable.Range(0, modulus);`

Now generate all valid modulus sequences for a given modulus. Thats easy too, just shift left or right a valid sequence we happen to know:

`private static IEnumerable<int> ShiftLeft(IEnumerable<int> sequence) { if (!sequence.Any()) yield break; var first = sequence.Take(1).First(); var tail = sequence.Skip(1); foreach (var i in tail) { yield return i; } yield return first; }`

And now you simply have to check if any given sequence contains all elements of a valid sequence and if it does, return the valid sequence.

I do note that I'm not ordering your list, I'm returning a new one or

`null`

if the sequence is not valid.`public static IEnumerable<int> GetOrderedSequence(IList<int> sequence, int modulus) { if (modulus < sequence.Count) throw new ArgumentOutOfRangeException(nameof(sequence), "Sequence can not contain more elements than specified modulus."); var modulusSequence = Enumerable.Range(0, modulus); for (var i = 0; i < modulus; i++) { var validSequence = modulusSequence.Take(sequence.Count); if (validSequence.All(item => sequence.Contains(item))) return validSequence; modulusSequence = ShiftLeft(modulusSequence); } return null; }`

Is this faster / more efficient than your approach? Probably not. Is it prettier? I think so but its debatable. Is it more flexible? Oh yes!

If you are absolutely sure you are only going to need to check `2`

and `3`

long sequences with modulus `4`

then you could keep your code. If not, implement a general purpose solution like the one I've shown you.