Vladimir Vargas - 1 year ago 141

Python Question

I'm trying to plot a polar plot with this code:

`import numpy as np`

import matplotlib.pylab as plt

def power(angle, l, lam):

return 1/(lam) * ((np.cos(np.pi*l*np.cos(angle)/lam) - np.cos(np.pi*l/lam))/np.sin(angle))**2

fig = plt.figure(1)

ax = fig.add_subplot(111, projection='polar')

theta = np.linspace(0.001, 2*np.pi, 100)

P1 = power(theta, 1, 5)

ax.plot(theta, P1, color='r', linewidth=3)

plt.savefig('1.png')

and I get this plot:

I would like to change 2 things. The first and more important one is to hide the radial tick labels (I just want to show the general form of the plot).

If possible, how can I choose the vertical axis to correspond to 0°?

Thanks for your help.

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Answer Source

You can use `set_yticklabels()`

to remove the radial ticks and `set_theta_zero_location()`

to change the zero location:

```
fig = plt.figure(1)
ax = fig.add_subplot(111, projection='polar')
ax.plot(theta, P1, color='r', linewidth=3)
ax.set_yticklabels([])
ax.set_theta_zero_location('N')
plt.show()
```

You might also want to change the direction of the azimuthal axis:

```
ax.set_theta_direction(-1)
```

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