Tibor Tibor -4 years ago 194
PHP Question

PHP constructor to return a NULL

I have this code. Is it possible for a

User
object constructor to somehow fail so that
$this->LoggedUser
is assigned a
NULL
value and the object is freed after constructor returns?

$this->LoggedUser = NULL;
if ($_SESSION['verbiste_user'] != false)
$this->LoggedUser = new User($_SESSION['verbiste_user']);

Answer Source

Assuming you're using PHP 5, you can throw an exception in the constructor:

class NotFoundException extends Exception {}

class User {
    public function __construct($id) {
        if (!$this->loadById($id)) {
             throw new NotFoundException();
        }
    }
}

$this->LoggedUser = NULL;
if ($_SESSION['verbiste_user'] != false) {
    try {
        $this->LoggedUser = new User($_SESSION['verbiste_user']);
    } catch (NotFoundException $e) {}
}

For clarity, you could wrap this in a static factory method:

class User {
    public static function load($id) {
        try {
            return new User($id);
        } catch (NotFoundException $unfe) {
            return null;
        }
    }
    // class body here...
}

$this->LoggedUser = NULL;
if ($_SESSION['verbiste_user'] != false)
    $this->LoggedUser = User::load($_SESSION['verbiste_user']);

As an aside, some versions of PHP 4 allowed you to set $this to NULL inside the constructor but I don't think was ever officially sanctioned and the 'feature' was eventually removed.

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