Nona Urbiz Nona Urbiz - 9 months ago 80
C# Question

A method to count occurrences in a list

Is there a simple way to count the number of occurrences of all elements of a list into that same list in C#?

Something like this:

using System;
using System.IO;
using System.Text.RegularExpressions;
using System.Collections.Generic;
using System.Linq;

string Occur;
List<string> Words = new List<string>();
List<string> Occurrences = new List<string>();

// ~170 elements added. . .

for (int i = 0;i<Words.Count;i++){
Words = Words.Distinct().ToList();
for (int ii = 0;ii<Words.Count;ii++){Occur = new Regex(Words[ii]).Matches(Words[]).Count;}
Occurrences.Add (Occur);
Console.Write("{0} ({1}), ", Words[i], Occurrences[i]);

Answer Source

How about something like this ...

var l1 = new List<int>() { 1,2,3,4,5,2,2,2,4,4,4,1 };

var g = l1.GroupBy( i => i );

foreach( var grp in g )
  Console.WriteLine( "{0} {1}", grp.Key, grp.Count() );

Edit per comment: I will try and do this justice. :)

In my example, it's a Func<int, TKey> because my list is ints. So, I'm telling GroupBy how to group my items. The Func takes a int and returns the the key for my grouping. In this case, I will get an IGrouping<int,int> (a grouping of ints keyed by an int). If I changed it to (i => i.ToString() ) for example, I would be keying my grouping by a string. You can imagine a less trivial example than keying by "1", "2", "3" ... maybe I make a function that returns "one", "two", "three" to be my keys ...

private string SampleMethod( int i )
  // magically return "One" if i == 1, "Two" if i == 2, etc.

So, that's a Func that would take an int and return a string, just like ...

i =>  // magically return "One" if i == 1, "Two" if i == 2, etc.

But, since the original question called for knowing the original list value and it's count, I just used an integer to key my integer grouping to make my example simpler.