B. Hanel B. Hanel - 1 year ago 101
Python Question

Comparing scalars to Numpy arrays

What I am trying to do is make a table based on a piece-wise function in Python. For example, say I wrote this code:

import numpy as np
from astropy.table import Table, Column
from astropy.io import ascii
x = np.array([1, 2, 3, 4, 5])
y = x * 2
data = Table([x, y], names = ['x', 'y'])
ascii.write(data, "xytable.dat")
xytable = ascii.read("xytable.dat")
print xytable

This works as expected, it prints a table that has
values 1 through 5 and
values 2, 4, 6, 8, 10.

But, what if I instead want
to be
x * 2
only if
is 3 or less, and
to be
x + 2

If I add:

if x > 3:
y = x + 2

it says:

The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

How do I code my table so that it works as a piece-wise function?

Answer Source

You can possibly use numpy.where():

In [196]: y = np.where(x > 3, x + 2, y)

In [197]: y
Out[197]: array([2, 4, 6, 6, 7])

The code above gets the job done in a fully vectorized manner. This approach is generally more efficient (and arguably more elegant) than using list comprehensions and type conversions.

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