Ryker - 11 months ago 38

Python Question

I had the following question. Namely, suppose I have an excel file with some names in the first row. Then the next however many rows are single letter entries (so "A", "B", "C" and so on).

My goal is to extract the column and make it into a list, so that, say, for column 1 the list would start in row 2, the next entry would be from row 3, and so on, until the end is reached.

How would I do that in Python?

Answer

I figured out the answer. Assuming the Excel file is *Test.xlsx*, we can translate the j-th column (excluding the first row) into list_j as follows:

```
book = xlrd.open_workbook("Test.xlsx")
sheet = book.sheet_by_index(0)
list_j = []
for k in range(1,sheet.nrows):
list_j.append(str(sheet.row_values(k)[j-1]))
```

Source (Stackoverflow)