Jeroen - 11 days ago 4x

C++ Question

I am wondering whether it is possible to write a code that commpares two numbers and when the second number is 'x' higher/lower than the first number do something. I wrote an example code to make it a bit more clear. Help is appreciated, thanks!

`int main()`

{

int first = 0;

int second = 0;

cin >> first;

cin >> second;

if (second = 0.5 > first) //I assumed it would look close to this. This obv isnt working but I cant figure out the correct way.

{

cout << "Too big\n";

}

else if (second = 0.5 < first)

{

cout << "Too low\n";

}

else {

cout << "Calculation will be made\n";

}

return 0;

}

So in this example, when the second number is between the range of 0.5 compared to the first number the code will proceed.

Answer

If you want the amount to check by a certain amount, change your condition to this:

```
if (second - first > 0.5)
{
cout << "Too Big!\n";
}
else if (second - first < 0.5)
{
cout << "Too low\n";
}
```

This would check if the difference between the 2 nunbers fits the criteria you want. Also, change the types of your numbers to `double`

, since currently truncation will compare the wrong numbers. For example in checking the value with a variable, try this:

```
int main()
{
double first = 0;
double second = 0;
double x = 0;
cin >> first;
cin >> second;
cin >> x;
if (second - first > x) {
cout << "Too Big!\n";
}
else if (second - first < x) {
cout << "Too low\n";
}
else {
cout << "Calculation will be made\n";
}
return 0;
}
```

Source (Stackoverflow)

Comments