Sarah - 2 years ago 72

R Question

Is there a way to run a model (for simplicity, a linear model) using specified columns of a data.frame?

For example, I would like to be able to do something like this:

`set.seed(1)`

ET = runif(10, 1,20)

x1 = runif(10, 1,20)

x2 = runif(10, 1,30)

x3 = runif(10, 1,40)

Xdf = data.frame(ET = ET, X1 = x1, X2 =x2, X3 = x3)

lm(ET~Xdf[,c(2,3)], data = Xdf)

Where the linear model would be equal to

`lm(ET~X1 +X2, data = Xdf)`

I have tried with a matrix - but it won't work in this case as I will eventually be adding spatial correlation based upon values stored in the data.frame that need to be specified by the data = data.frame call.As well as having certain names.frame. As well, I need to be able to choose certain columns in the data because this will be looping through multiple models using different predictors.

Any help would be greatly appreciated. Thanks!

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Answer Source

Here's a (rather ugly) way to make it work.

I use `as.formula`

and the `paste`

function to make the formula before calling `lm`

.

I'm sure there are better ways to do this, but this is what came to mind.

```
# ET ~ X1 + X2
f1 <- as.formula(paste("ET~", paste(names(Xdf)[c(2,3)],
collapse="+")))
lm(f1, data=Xdf)
```

You can also specify the individual columns, though it might be more work

```
lm(ET ~ Xdf[,2] + Xdf[,3], data=Xdf)
```

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