IanHacker - 1 month ago 4x

Python Question

I'm porting a MATLAB R2011b code to Python 3.5.1.

The original MATLAB code, which was written around 10 years ago, contains a 'time' function as bellow:

`t_x=time(x,fsample);`

The output is:

`debug> x`

x =

-0.067000 -0.067000 -0.068000 -0.069000 -0.069000 -0.070000 -0.070000 -0.071000 -0.071000 -0.072000

debug> fsample

fsample = 10000

debug> t_x

t_x =

0.00000 0.10000 0.20000 0.30000 0.40000 0.50000 0.60000 0.70000 0.80000 0.90000

I'd like to do the same thing in Python, but I cannot find any equivalent function in Python. (The function name 'time' is too general that it's hard to search on Google.) It seems this 'time' function returns 1000/fsample (e.g., if fsample=10000, then 0.1) multiplied by the index of 'x'. Does anyone know a similar function in Python?

... Please note that this 'time' function is different from the 'time' function introduced in MATLAB R2014b:

[http://www.mathworks.com/help/matlab/ref/time.html?searchHighlight=time&s_tid=gn_loc_drop][1]

Answer

It should be simple enough to implement a similar function.

For numpy arrays

```
import numpy as np
def time(x, fsample):
return np.linspace(0, (1000/fsample)*(len(x) - 1), num=len(x))
```

For simple python lists

```
def time(x, fsample):
return [i*(1000/fsample) for i in range(len(x))]
```

Source (Stackoverflow)

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