user2476714 user2476714 - 1 year ago 47
Linux Question

How do I grep out multiple lines of the same pattern?

I have a log file that is filled with exceptions that is not useful to me.

It is being generated every two second and when looking at log file that contains 24 hrs of logging it becomes overwhelming to get to the relevant info I need.

My logs look something like this:

2013-04-21 00:00:00,852 [service name] ERROR java-class - Exception
at ......
at java.apache ....
and 28 more lines like these.

I want to clean up the copy of the log to another file.

Obviously grep -v "string" -A29 foo.log > new_file.log doesn't help me filter out those 30 lines.

I also tried several sed and awk statements I saw for similar issues others where having. But none of them seem to help.

I am more of network admin getting my feet wet on linux systems.

Can somebody please help?

Answer Source

This might work for you (GNU sed):

sed '/ERROR java-class - Exception/{:a;$!N;/\n\s*at\s.*/s///;ta;D}' file >new_file

This gathers up all the lines following ERROR java-class - Exeption that begin with spaces followed by at ... into one line and then deletes that line. Using the above as a template other exceptions could be filtered in the same manner.