Reversing chars in C

Question

I was looking at a function that reverses an array of

char

s and I get everything, but the one thing that confuses me is the last statement inside the last

for

loop which is

line[j] = temp;

. I don't know what this is accomplishing.

    void reverse(char line[]) {



    char temp;

    int i, j;



    for (j = 0; line[j] != '\0'; ++j)

        ;

    --j;



    if (line[j] == '\n') {

        --j;

    }



    for (i = 0; i < j; ++i, --j) {

        temp = line[i];



        line[i] = line[j];



        //This statement is the one in which I dont understand it's function

        line[j] = temp;

    }

}

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Answer 1

you simply want to exchange two variables inside an array together . you won't be able to just do line[i] = line[j]; because the i'th item of the 'line' array will be overwritten by the j'th variable and it's initial value will be lost. so, in order to avoid i'th item from being lost, you first copy it in the 'temp' (temp= line[i]) , you overwrite line[i] by line[j], then copy temp (which is your initial value of line[i])to line[j].

Reversing chars in C

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