jari van m jari van m - 1 month ago 8
Javascript Question

screeps - can't make variable in source

I am new to Screeps (love it) and I am having a hard time to create a variable for all sources in the room.
I am trying to make sure only 3 creeps work on the same source, so I have following code-snippet for my harvester and my main module

Main

var sources = Game.spawns.Spawn1.room.find(FIND_SOURCES);
for (var a in sources) {
var source = (sources[a]);
source.memory.numPeopleAt = 0;
}
module.exports.loop = function () {
...
}


harvester

var sources = creep.room.find(FIND_SOURCES);
for (var s in sources) {
if (creep.harvest(sources[s]) == ERR_NOT_IN_RANGE && sources[s].memory.numPeopleAt < 3) {
creep.moveTo(sources[s]);
sources[s].memory.numPeopleAt++;
break;
}
}


I know I still have to make a function that does
sources[s].memory.numPeopleAtt--


Thanks in advance,

Jari Van Melckebeke

Answer

Source doesn't have a memory property like Creep does. However, you can add something to the main memory object.

var sources = Game.spawns.Spawn1.room.find(FIND_SOURCES);
if (!Memory.sources) {
    Memory.sources = {};
}
_.each(sources, function(source) {
    if (!Memory.sources[source.id]) {
        Memory.sources[source.id] = { numPeopleAt: 0 };
    }
});

One thing to note is that your code will run every game tick, so you only need to initialize something if it hasn't already been initialized (that's what the if-checks are for).

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