Josh Hunt Josh Hunt - 7 months ago 24
Python Question

Django: Print url of view without hardcoding the url

Can i print out a url

of a certain view in a template?

Here is the rule i want to create a link for

(r'^manage/products/add/$', create_object, {'model': Product, 'post_save_redirect': ''}),

I would like to have /manage/products/add in a template without hardcoding it. How can i do this?

Edit: I am not using the default admin (well, i am but it is at another url), this is my own


You can use get_absolute_url, but that will only work for a particular object. Since your object hasn't been created yet, it won't work in this case.

You want to use named URL patterns. Here's a quick intro:

Change the line in your to:

(r'^manage/products/add/$', create_object, {'model': Product, 'post_save_redirect': ''}, "create-product"),

Then, in your template you use this to display the URL:

{% url create-product %}

If you're using Django 1.5 or higher you need this:

{% url 'create-product' %}

You can do some more powerful things with named URL patterns, they're very handy. Note that they are only in the development version (and also 1.0).