user56690 - 2 years ago 140
Java Question

# java any digit armstrong number

i have written the below code for getting a three digit armstrong number.

``````public class test {
public static void main(String args[]){

for (int i = 100; i <= 999; i++){
int firstDigit = (i / 100);
int secondDigit = (i % 100) / 10;
int thirdDigit = (i % 10);
if ((firstDigit * firstDigit * firstDigit) +
(secondDigit * secondDigit * secondDigit) +
(thirdDigit * thirdDigit * thirdDigit) == i) {

System.out.println("this is a armstriong number - "+i);
}
} } }
``````

I am trying to get a ANY digit armstrong based on users input, but i am ending up writing too much loops and code.

The following code check if the scanned number (on console) is a Armstrong number. I've tested it, it works fine.

TEST IN CONSOLE

``````import java.util.Scanner;

class ArmstrongNumber
{
public static void main(String args[])
{
int n, sum = 0, temp, remainder, digits = 0;

Scanner in = new Scanner(System.in);
System.out.println("Input a number to check if it is an Armstrong number");
n = in.nextInt();

temp = n;

// Count number of digits

while (temp != 0) {
digits++;
temp = temp/10;
}

temp = n;

while (temp != 0) {
remainder = temp%10;
sum = sum + power(remainder, digits);
temp = temp/10;
}

if (n == sum)
System.out.println(n + " is an Armstrong number.");
else
System.out.println(n + " is not an Armstrong number.");
}

static int power(int n, int r) {
int c, p = 1;

for (c = 1; c <= r; c++)
p = p*n;

return p;
}
}
``````

WITH A FUNCTION

If you need to use it as a function, please try this. The `n` param is the number you want to check. My function return true if it is an Armstrong number, else it returns false.

``````public boolean isArmstrongNumber(int n) {
int sum = 0, temp = n, remainder, digits = 0;
while (temp != 0) {
digits++;
temp = temp/10;
}

temp = n;

while (temp != 0) {
remainder = temp%10;
sum = sum + power(remainder, digits);
temp = temp/10;
}
if (n == sum) //Armstrong number
return true;
else //Not Armstrong number
return false;
}
``````
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