jcjunction jcjunction - 5 months ago 98
Javascript Question

JavaScript transitive equality

Learning JavaScript and found that given the expression below, it evaluates to true when given this:

transitive([1], 1, {toString:_=>'1'});

I don't understand why.

it makes sense that the y and z are equal but how can the x and y be equal if the x and z are not equal?

function transitive(x,y,z) {
return x && x == y && y == z && x != z;


In JavaScript there is a concept of "truthiness" and "falsyness". Values like 1 and '1' are equal when compared with a loose comparison operator like ==, but are not strictly equal using a strict equality operator like ===.

The object is equal to 1 because JavaScript uses type coercion to convert the object to a comparable value to a primitive. It does this by calling the .toString() method of the object, which returns '1' and as we learned above is truthy, as is 1, so they are considered equal when using ==.

This will probably be relevant: MDN: Equality comparisons and sameness.

It is best/common practice in JavaScript to always use === and !== in place of == and !=.