Roman Roman Roman Roman - 8 months ago 37
Javascript Question

Javascript set base object when declare methods in prototype

I read that declaring object methods in prototype is good approach because it saves memory and allows to change implementation in any time for all objects.
But what i need to do when i need to set base object for object that uses prototype method declaration?

function Animal() {
this.age = 0;
this.weight = 0;
//other properties

Animal.prototype = {
//some methods for Animal

function Dog() {
//properties for Dog

Dog.prototype = {
//some methods for Dog

So, how can i set Animal as a base class(object) for Dog(because prototype property in Dog is implemented as custom object for methods)?

Answer Source

ES5 version (still most common, but I wouldn't recommend it - see ES6 version)

Based on this post here you need to use Object.create like this:

function Animal() {}
Animal.prototype = {};

function Dog() {}
Dog.prototype = Object.create( Animal.prototype );

Also see this solution with Object.assign (sadly IE doesn't support it)

ES6 version

class Animal {
  // all your methods come in here. No more prototype needed.

class Dog extends Animal {


You can already use ES6 even though most browsers don't completely support it yet. Use babel to transpile you JS.

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