Austin A Austin A - 7 months ago 121
Bash Question

How do you run a .exe with parameters using vba's shell()?

I have a target file path that is structured like example below.

C:\Program Files\Test\foobar.exe /G


What I need to do is be able to execute this file using vba's
shell()
command.

How do I have to format the file path to tell
Shell()
that there is an argument that it needs to call along with running the .exe

What I've read/tried (with no avail) is below with the results to the right.

file = """C:\Program Files\Test\foobar.exe"" /G" <---Bad file name or number (Error 52)
shell(file)

file2 = "C:\Program Files\Test\foobar.exe /G" <---file never found
shell(file2)


I've succeeded with running other .exe's using shell() so I know it's not a problem with vba or the function.

Example:

works = "C:\Program Files\Test\test.exe"
shell(works)


I'm not particularly familiar with the process involved with executing files that require additional parameters so if I misspeak or you need more information, please let me know.

Answer

This works for me (Excel 2013):

Public Sub StartExeWithArgument()
    Dim strProgramName As String
    Dim strArgument As String

    strProgramName = "C:\Program Files\Test\foobar.exe"
    strArgument = "/G"

    Call Shell("""" & strProgramName & """ """ & strArgument & """", vbNormalFocus)
End Sub

With inspiration from here http://stackoverflow.com/a/3448682.

Comments