ashishl ashishl - 1 month ago 7x
JSON Question

Getting syntax error for Spring security with Jersey Rest API

I am doing authentication for REST Services.

So If user is unauthenticated then I want to send the user as "unauthenticated user" as repsonse in JSON format.

below is my code . I have set the content type as APPLICATION_JSON then I am getting the response as syntax error on postman tool. I can see the exact error in plainText or in Xml but not able to see the response in JSON.

Could anybody help me to get out from this issu please.

public void commence(HttpServletRequest request, HttpServletResponse response,
AuthenticationException authException) throws IOException {

response.setHeader("Connection", "keep-alive");
String msg = authException.getMessage();
response.getOutputStream().println("{ \"error\": \"" + msg+ "\" }");


I think you are doing it in wrong way the method syntax in ServeletResponse class is:

void setContentType(java.lang.String type)

so it should be like this


Hope this helps.