I am developing an application for Android and I am using a popup window when the user clicks a specific menu bar object(consisting of small images lined up horizontally) on the bottom of the screen.
On the click I want the popup window to be anchored to the top-left corner of the view that was clicked and be shown on top.
The only methods that seem to be relevant are showAsDropDown(View anchor, int xoff, int yoff) and showAtLocation(View parent, int gravity, int x, int y). The problem with showAsDropDown is that it is anchored to the bottom-left corner of the view.
Is there another way to implement this?
popupWindow.showAtLocation(...) actually shows the window absolutely positioned on the screen (not even the application). The anchor in that call is only used for its window token. The coordinates are offsets from the given gravity.
What you actually want to use is:
popupWindow.showAsDropDown(anchor, offsetX, offsetY, gravity);
This call is only available in API 19+, so in earlier versions you need to use:
popupWindow.showAsDropdown(anchor, offsetX, offsetY);
These calls show the popup window relative to the specified anchor view. Note that the default gravity (when calling without specified gravity) is
Gravity.TOP|Gravity.START so if you are explicitly using
Gravity.LEFT in various spots in your app you will have a bad time :)