dmikester1 dmikester1 - 1 month ago 5
MySQL Question

How to transpose mysql table rows into columns

Here is what my current mysql table looks like:

PunchID EmpID PunchEvent PunchDateTime
1 0456 clockin 5/14/2013 8:36:26 AM
48 0456 breakout 5/14/2013 12:01:29 PM
53 0456 breakin 5/14/2013 12:28:31 PM
54 0456 clockout 5/14/2013 2:28:33 PM
57 0456 clockin 5/15/2013 7:38:34 AM
58 0456 breakout 5/15/2013 7:38:39 AM
59 0456 breakin 5/15/2013 7:38:41 AM
60 0456 clockout 5/15/2013 7:38:42 AM


Now I want to return a result set that is grouped based on the day of the week like so:

Day ClockIn BreakOut BreakIn ClockOut
Tuesday 8:36:26 AM 12:01:29 PM 12:28:31 PM 2:28:33 PM
Wednesday 7:38:34 AM etc, etc...


This is my current query. But it only returns the first punch for each day.

SELECT DATE_FORMAT(PunchDateTime, '%W') as day, PunchEvent, DATE_FORMAT(PunchDateTime, '%l:%m:%s %p') as time FROM timeclock_punchlog WHERE EmpID = '0456' GROUP BY DATE(PunchDateTime) ORDER BY PunchDateTime ASC;


Can someone help me with this?
Thanks
Mike

Answer
SELECT  DATE_FORMAT(PunchDateTime, '%W') DAY,
        MAX(CASE WHEN PunchEvent = 'ClockIn' THEN DATE_FORMAT(PunchDateTime, '%r') END) ClockIn,
        MAX(CASE WHEN PunchEvent = 'BreakOut' THEN DATE_FORMAT(PunchDateTime, '%r') END) BreakOut,
        MAX(CASE WHEN PunchEvent = 'BreakIn' THEN DATE_FORMAT(PunchDateTime, '%r') END) BreakIn,
        MAX(CASE WHEN PunchEvent = 'ClockOut' THEN DATE_FORMAT(PunchDateTime, '%r') END) ClockOut
FROM    tableName
WHERE   EmpID = 456
GROUP   BY DATE_FORMAT(PunchDateTime, '%W')
ORDER   BY PunchDateTime

OUTPUT

╔═══════════╦═════════════╦═════════════╦═════════════╦═════════════╗
║    DAY    ║   CLOCKIN   ║  BREAKOUT   ║   BREAKIN   ║  CLOCKOUT   ║
╠═══════════╬═════════════╬═════════════╬═════════════╬═════════════╣
║ Tuesday   ║ 08:36:26 AM ║ 12:01:29 PM ║ 12:28:31 PM ║ 02:28:33 PM ║
║ Wednesday ║ 07:38:34 AM ║ 07:38:39 AM ║ 07:38:41 AM ║ 07:38:42 AM ║
╚═══════════╩═════════════╩═════════════╩═════════════╩═════════════╝
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