wener wener - 1 year ago 91
Linux Question

How to use sed to replace every match according to each match?

$ echo 'a,b,c,d=1' | sed '__MAGIC_HERE__'
a=1,b=1,c=1,d=1
$ echo 'a,b,c,d=2' | sed '__MAGIC_HERE__'
a=2,b=2,c=2,d=2


Dose sed can cast this spell ?

EDIT

I have to use sed twice to achieve this

s='a,b,c,d=2'
v=`echo $s | sed -rn 's/.*([0-9]+)/\1/p'`
echo $s | sed "s/=.*//" | sed -rn "s/([a-z])/\1=$v/gp"


OR

s='a,b,c,d=2'
echo $s | sed -rn 's/.*([0-9]+)/\1/p' | { read v;echo $s | sed "s/=.*//" | sed -rn "s/([a-z])/\1=$v/gp"; }


EDIT

The real use case is here and there is multiline content, Thanks to @hek2mgl, the awk is way more easier.

EDIT

My usecase

export LS_COLORS='no=00:fi=00:di=01;34:ln=01;36:pi=40;33:so=01;35:do=01;35:bd=40;33;01:cd=40;33;01:or=40;31;01:ex=01;32'


exts="
tar|tgz|arj|taz|lzh|zip|z|Z|gz|bz2|deb|rpm|jar=01;31
jpg|jpeg|gif|bmp|pbm|pgm|ppm|tga|xbm|xpm|tif|tiff|png=01;34
mov|fli|gl|dl|xcf|xwd|ogg|mp3|wav=01;35
flv|mkv|mp4|mpg|mpeg|avi=01;36
"

# SED Version

read -rd '' exts < <(
for i in $(echo $exts)
do
echo $i | sed -rn 's/.*=(.*)/\1/p' | { read v; echo $i | sed "s/=.*//" | sed -rn "s/([^|]+)\|?/:\*.\1=$v/gp"; }
done | tr -d '\n'
)
export LS_COLORS="$LS_COLORS$exts"

# AWK Version
read -r -d '' exts < <( echo $exts | xargs -n1 | awk -F= '{gsub(/\|/,"="$2":*.")}$2' | tr "\n" ":" )
export LS_COLORS="$LS_COLORS:*.$exts"

unset exts


EDIT

Finale sed version

read -r -d '' exts < <( echo $exts | xargs -n1 | sed -r 's/\|/\n/g;:a;s/\n(.*(=.*))/\2:*.\1/;ta' | tr "\n" ":" )

Answer Source

This might work for you (GNU sed):

sed -r 's/,/\n/g;:a;s/\n(.*(=.*))/\2,\1/;ta' file

Convert the separators to newlines (a unique character not found in the file) and then replace each occurrence of the newline by the required string and the original separator.

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