user3454730 user3454730 - 2 months ago 9
PHP Question

Warning: mysqli_stmt_bind_param() expects parameter 1 to be mysqli_stmt, boolean given?

this is the first time ever that I am trying to secure my code against sql injection using

mysqli prepared statement
. so please be gentle and explain things in simple terms so I can understand it.

Now I am using the following code which I thought i was right but it throws these errors and I do not understand that at all.

here is the errors:

Warning: mysqli_stmt_bind_param() expects parameter 1 to be mysqli_stmt, boolean given in on line 92

Warning: mysqli_stmt_execute() expects parameter 1 to be mysqli_stmt, boolean given in on line 93

Warning: mysqli_stmt_close() expects parameter 1 to be mysqli_stmt, boolean given in on line 96


here is the code:

$stmt = mysqli_prepare(
$db_conx,
"INSERT $storenameTable (firstname, lastname, username, address_1, address_2, postcode, country, county, city, email, password, storeShop, signupdate) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"
);
//after validation, of course
mysqli_stmt_bind_param($stmt, "issi", $firstname, $lastname, $username, $address_1, $address_2, $postcode, $country, $county, $city, $email, $hashedPass, $storenameTable);
mysqli_stmt_execute($stmt); <//<<<<<<<< line 92
if (mysqli_affected_rows($db_conx)) <//<<<<<<<< line 93
{
mysqli_stmt_close($stmt); <//<<<<<<<< line 96
//update was successful
$id = mysqli_insert_id($db_conx);
}


i would appreciate your help.

Answer

It seems that you have a missing parameter, you should have 13 parameters and 13 ? check the two parameters after password. (I took out signupdate) try the below :

$stmt = mysqli_prepare(
    $db_conx,
    "INSERT INTO $storenameTable (firstname, lastname, username, address_1, address_2, postcode,  country, county, city, email, password, storeShop) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"
);
//after validation, of course
mysqli_stmt_bind_param($stmt, "issi", $firstname, $lastname, $username, $address_1, $address_2, $postcode, $country, $county, $city, $email, $hashedPass, $storenameTable);
mysqli_stmt_execute($stmt);     <//<<<<<<<< line 92
if (mysqli_affected_rows($db_conx))     <//<<<<<<<< line 93
{
    mysqli_stmt_close($stmt);  <//<<<<<<<< line 96
    //update was successful
    $id = mysqli_insert_id($db_conx);
}

You also can get more details on the last error by using var_dump(mysqli_error($db_conx));