derek - 1 year ago 94
C Question

# sorting arrays in c with pointers

I am trying to sort an array from least to greatest using pointers instead of array subscripts. I am not sure where the problem is but when i run this code, the values are returned in the same order that they were entered. The find_largest and swap functions both do exactly what they say. The selection_sort function uses a for loop to sort the numbers from right to left (greatest to smallest, right to left). I have been staring at this for a while now and it looks like it should work fine but like i said, for some reason the numbers are returned in the same order they were entered.
Here is my code:

``````#include <stdio.h>

#define N 5

void selection_sort(int *a, int n);
int *find_largest(int *a, int n);
void swap(int *p, int *q);

int main(void)
{
int i;
int a[N];

printf("Enter %d numbers to be sorted: ", N);
for (i = 0; i < N; i++)
scanf("%d", (a+i));

selection_sort(a, N);

printf("In sorted order:");
for (i = 0; i < N; i++)
printf(" %d", *(a+i));
printf("\n");

return 0;
}

void selection_sort(int *a, int n)
{
int i = 0;
int *largest;

for(i = 0; i < n; i++){
largest = find_largest(a, n-i);
swap(largest, a+(n-1-i));
}

}

int *find_largest(int *a, int n){
int *p = a;
int *largest = p;
for(p = a; p < a+n-1; p++){
if(*(p+1) > *p){
largest = (p + 1);
}
}
return largest;
}

void swap(int *p, int *q){
int *temp;
temp = p;
p = q;
q = temp;
}
``````

There are two mistakes in your code. One, logical in the find_largest function:

``````int *find_largest(int *a, int n){
int *p = a;
int *largest = p;
for(p = a; p < a+n-1; p++){
if(*(p+1) > *largest){     <---- //here you were checking for *(p)
largest = (p + 1);
}
}
return largest;

}
``````

the other is with pointers in swap function:

``````void swap(int *p, int *q){
int temp;
temp = *p;
*p = *q;
*q = temp;
}
``````
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