over.unity - 7 months ago 37

Python Question

Suppose that I have a numpy like this

`a = np.array([[0, 0, 0, 1373, 1371, 1365, 1371, 1375],`

[0, 0, 0, 1388, 1371, 1365, 1301, 1302]])

I have to find all value pairs (compare idx 0 == 1).

for example:

`pairs = (a[0] == a[1])`

# [ True True True False True True False False]

but now, I'd like to have the idx's as result without comparing the zero values.

for example:

`[4, 5]`

This is an example, in my case I have around 100k datapoints. I'd like to find an efficient way.

Answer

```
In [14]: result = [r[0] for r in np.argwhere(a[0,:] == a[1,:]) if a[0, r] != 0]
In [15]: result
Out[15]: [4, 5]
```

Source (Stackoverflow)