Freddie R - 1 year ago 99

Python Question

I am working on an algorithm to automatically create character sheets for a roleplaying game. In the game, you have attributes which you put points into to increase them. However, at a certain value it takes 2 points to increase the value of the actual attribute by 1. You start of with a certain number of points, and each attribute has a value of 1 by default

I have a program that randomly assigns the points, however I am stuck as to how I then change these values (that are in a dictionary) to round down when necessary.

For example, if I put 3 points in "strength", thats fine, I get a "strength" value of 3 (including tha base 1). However, if I put 4 points in, I still should only have a value of 4. It should take 5 points (plus the base 1) in order to get a value of 5. It then takes another 2 points to get a value of 6, 3 points to get a value of 7 and 3 points to get a value of 8.

The code I am currently using to assign the attibutes looks like this:

`attributes = {}`

row1 = ['strength', 'intelligence', 'charisma']

row2 = ['stamina', 'willpower']

row3 = ['dexterity', 'wits', 'luck']

def assignRow(row, p): # p is the number of points you have to assign to each row

rowValues = {}

for i in range(0, len(row)-1):

val = randint(0, p)

rowValues[row[i]] = val + 1

p -= val

rowValues[row[-1]] = p + 1

return attributes.update(rowValues)

assignRow(row1, 7)

assignRow(row2, 5)

assignRow(row3, 3)

What I want is just a simple function that takes the dictionary "attributes" as a parameter, and converts the number of points each attribute has to the proper value it should be.

i.e.

`"strength": 4`

`"strength": 4`

`"wits": 6"`

`"wits": 5"`

`"intelligence: 9`

`"intelligence: 7"`

I'm somewhat new to using dictionaries and so the ways I would normally approach this:

`def convert(list):`

for i in range(len(list)):

if list[i] <= 4:

list[i] = list[i]

if list[i] in (5, 6):

list[i] -= 1

if list[i] in (7, 8):

list[i] -= 2

if list[i] in (9, 10):

list[i] = 6

if list[i] in (11, 12, 13):

list[i] = 7

else:

list[i] = 8

Not efficient or pretty but still a solutuion. However, you can't just loop over indexes in a dictionary so I am not entirely sure how to go about something like this.

General explanation or function would be appreciated.

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Answer Source

Seems that bisection algo suits your needs pretty well - points to "invest" is always sorted and defined. Create array with reference points and you're good to without bunch of `if`

s:

```
>>> from bisect import bisect
>>> points_to_invest = [1, 2, 3, 4, 6, 8, 10, 13]
>>> bisect(points_to_invest, 1)
1
>>> bisect(points_to_invest, 4)
4
>>> bisect(points_to_invest, 5)
4
>>> bisect(points_to_invest, 6)
5
```

This approach will give you way easier maintainability for future

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