How to print a function's return string without its body?

Question

I have an html document that contains 4 paragraphs.

I want to take the concatenation of all paragraph's innerHTML and put it in the paragraph with "demo" id. The problem is that it also prints the function's signature...

How can I print only the string that my function returns?

<!DOCTYPE html>

<html>

<body>



<p>Hello World!</p>



<p>The DOM is very useful.</p>

<p>This example demonstrates the <b>getElementsByTagName</b> method</p>



<p id="demo"></p>



<script >

    var paragraphs = document.getElementsByTagName("p");





    function getText() {

        var text=null;

        for (var i = 0; i < paragraphs.length; i++) {

            getText = getText + paragraphs[i].innerHTML;

        }

        return getText;

    }



    document.getElementById("demo").innerHTML=getText();



</script>



</body>

</html>

I get this as a result:

Hello World!

The DOM is very useful.

This example demonstrates the getElementsByTagName method

function getText() { var text=null; for (var i = 0; i <
paragraphs.length; i++) { getText = getText + paragraphs[i].innerHTML;
} return getText; }Hello World!The DOM is very useful.This example
demonstrates the getElementsByTagName method

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Answer 1

Replace your function with :

function getText() {
        var text="";
        for (var i = 0; i < paragraphs.length; i++) {
            text= text+ paragraphs[i].innerHTML;
        }
        return text;
    }

In your case, you were returning getText which is name of your function that's why the method is also getting appended

How to print a function's return string without its body?

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