Say I have the classic 4-byte signed integer, and I want something like
to give me something like
In reality, the above gives me -0x1. I'm dawdling about in some lower level language, and python commandline is quick n easy.
So.. is there a way to do it?
This will do the trick:
>>> print hex (-1 & 0xffffffff) 0xffffffffL
or, in function form (and stripping off the trailing "L"):
>>> def hex2(n): ... return hex (n & 0xffffffff)[:-1] ... >>> print hex2(-1) 0xffffffff >>> print hex2(17) 0x11
or, a variant that always returns fixed size (there may well be a better way to do this):
>>> def hex3(n): ... return "0x%s"%("00000000%s"%(hex(n&0xffffffff)[2:-1]))[-8:] ... >>> print hex3(-1) 0xffffffff >>> print hex3(17) 0x00000011
Or, avoiding the hex() altogether, thanks to Ignacio and bobince:
def hex2(n): return "0x%x"%(n&0xffffffff) def hex3(n): return "0x%s"%("00000000%x"%(n&0xffffffff))[-8:]