Kurt Peek - 2 months ago 6

Python Question

I'm writing a Python script which is supposed to allow human and computer players to play Tic Tac Toe. To represent the board, I'm using a 3x3 Numpy array with

`1`

`0`

`import numpy as np`

class Board():

def __init__(self, grid = np.ones((3,3))*np.nan):

self.grid = grid

def winner(self):

rows = [self.grid[i,:] for i in range(3)]

cols = [self.grid[:,j] for j in range(3)]

diag = [np.array([self.grid[i,i] for i in range(3)])]

cross_diag = [np.array([self.grid[2-i,i] for i in range(3)])]

lanes = np.concatenate((rows, cols, diag, cross_diag))

if any([np.array_equal(lane, np.ones(3)) for lane in lanes]):

return 1

elif any([np.array_equal(lane, np.zeros(3)) for lane in lanes]):

return 0

So for example, if I execute

`board = Board()`

board.grid = np.diag(np.ones(3))

print board.winner()

I get the result

`1`

`any`

Answer

Another option is to check the sum of `lanes`

.

```
s = np.sum(lanes, axis=1)
if 3 in s:
return 1
elif 0 in s:
return 0
```

Source (Stackoverflow)

Comments