Dan Tao Dan Tao - 1 year ago 72
C# Question

What's the best way to ensure a base class's static constructor is called?

The documentation on static constructors in C# says:

A static constructor is used to
initialize any static data, or to
perform a particular action that needs
performed once only. It is called
automatically before the first
instance is created or any static
members are referenced

That last part (about when it is automatically called) threw me for a loop; until reading that part I thought that by simply accessing a class in any way, I could be sure that its base class's static constructor had been called. Testing and examining the documentation have revealed that this is not the case; it seems that the static constructor for a base class is not guaranteed to run until a member of that base class specifically is accessed.

Now, I guess in most cases when you're dealing with a derived class, you would construct an instance and this would constitute an instance of the base class being created, thus the static constructor would be called. But if I'm only dealing with static members of the derived class, what then?

To make this a bit more concrete, I thought that the code below would work:

abstract class TypeBase
static TypeBase()
Type<int>.Name = "int";
Type<long>.Name = "long";
Type<double>.Name = "double";

class Type<T> : TypeBase
public static string Name { get; internal set; }

class Program

I assumed that accessing the
class would automatically invoke the static constructor for
; but this appears not to be the case.
, and the code above outputs the empty string.

Aside from creating some dummy member (like a static
method that does nothing), is there a better way to ensure that a base type's static constructor will be called before any of its derived types is used?

If not, then... dummy member it is!

Answer Source

The rules here are very complex, and between CLR 2.0 and CLR 4.0 they actually changed in subtle and interesting ways, that IMO make most "clever" approaches brittle between CLR versions. An Initialize() method also might not do the job in CLR 4.0 if it doesn't touch the fields.

I would look for an alternative design, or perhaps use regular lazy initialization in your type (i.e. check a bit or a reference (against null) to see if it has been done).

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