Joseph Hwang Joseph Hwang - 2 months ago 17
Java Question

Java 8 stream to Map<Integer, List<String>>

This is java object to handle in java 8 stream

private static List<Person> getPersons() {
List<Person> results = new ArrayList<Person>();

results.add(new Person("Elsdon", "Jaycob", "Java programmer", "male", 43, 2000));
results.add(new Person("Tamsen", "Brittany", "Java programmer", "female", 23, 1500));
results.add(new Person("Floyd", "Donny", "Java programmer", "male", 33, 1800));
results.add(new Person("Sindy", "Jonie", "Java programmer", "female", 32, 1600));
results.add(new Person("Vere", "Hervey", "Java programmer", "male", 22, 1200));
results.add(new Person("Maude", "Jaimie", "Java programmer", "female", 27, 1900));
results.add(new Person("Shawn", "Randall", "Java programmer", "male", 30, 2300));
results.add(new Person("Jayden", "Corrina", "Java programmer", "female", 35, 1700));
results.add(new Person("Palmer", "Dene", "Java programmer", "male", 33, 2000));
results.add(new Person("Addison", "Pam", "Java programmer", "female", 34, 1300));

results.add(new Person("Jarrod", "Pace", "PHP programmer", "male", 34, 1550));
results.add(new Person("Clarette", "Cicely", "PHP programmer", "female", 23, 1200));
results.add(new Person("Victor", "Channing", "PHP programmer", "male", 32, 1600));
results.add(new Person("Tori", "Sheryl", "PHP programmer", "female", 21, 1000));
results.add(new Person("Osborne", "Shad", "PHP programmer", "male", 32, 1100));
results.add(new Person("Rosalind", "Layla", "PHP programmer", "female", 25, 1300));
results.add(new Person("Fraser", "Hewie", "PHP programmer", "male", 36, 1100));
results.add(new Person("Quinn", "Tamara", "PHP programmer", "female", 21, 1000));
results.add(new Person("Alvin", "Lance", "PHP programmer", "male", 38, 1600));
results.add(new Person("Evonne", "Shari", "PHP programmer", "female", 40, 1800));

return results;
}


And I generate Map objects with key-value "age". This is codes

Function<Person, Map<String, String>> nameNsalary = (Person p) -> {
Map<Int, String> map = new HashMap<Int,String>();

if (p.getAge()>=40)
map.put(40 , p.getFirstName() + " " + p.getLastName() +":" + p.getSalary());
else if(p.getAge()>=30 && p.getAge()<40)
map.put(30 , p.getFirstName() + " " + p.getLastName() +":" + p.getSalary());
else if(p.getAge()<20)
map.put(20 , p.getFirstName() + " " + p.getLastName() +":" + p.getSalary());
else
map.put(10 , p.getFirstName() + " " + p.getLastName() +":" + p.getSalary());

return map;
};

persons.stream().map(nameNsalary).forEach(System.out::println);


Output map object is successful like below,

{40=Elsdon Jaycob:2000}
{20=Tamsen Brittany:1500}
{30=Floyd Donny:1800}
{30=Sindy Jonie:1600}
{20=Vere Hervey:1200}
{20=Maude Jaimie:1900}
{30=Shawn Randall:2300}
{30=Jayden Corrina:1700}
{30=Palmer Dene:2000}
{30=Addison Pam:1300}
{30=Jarrod Pace:1625}
{20=Clarette Cicely:1260}
{30=Victor Channing:1680}
{20=Tori Sheryl:1050}
{30=Osborne Shad:1155}
{20=Rosalind Layla:1365}
{30=Fraser Hewie:1155}
{20=Quinn Tamara:1050}
{30=Alvin Lance:1680}
{40=Evonne Shari:1890}


But I fail changing output type from
Map<Integer, String>
to
Map<Integer, List<String>>
, for example,

30 = [Jayden Corrina:1700, Palmer Dene:2000, Addison Pam:1300]


I have no idea how to handle these Map object data to
Map<Int, List<String>>
. I made this code,

Map<Integer, List<String>> result = persons.stream().map(nameNsalary)
.collect(Collectors.toMap(mapper -> (Integer)mapper.getKey(), mapper -> mapper.getValue()));


But this code throws the following exception

Exception in thread "main" java.lang.Error: Unresolved compilation problems:
Type mismatch: cannot convert from Map<Object,Object> to Map<Integer,List<String>>
The method getKey() is undefined for the type Map<Integer,String>
The method getValue() is undefined for the type Map<Integer,String>


I am stuck with this procedure.
Your advice will be deeply appreciated. Best regards

Answer

Your mapper is quite inefficient, it creates a new map for every entry.

It would be simpler to use the groupingBy collector.

Map<Integer, List<String>> result = persons.stream()
        .collect(Collectors.groupingBy(
            p -> (p.getAge() / 10) * 10, // some integer division trick
            Collectors.mapping(
                p -> p.getFirstName() + " " + p.getLastName() +":" + p.getSalary(),
                Collectors.toList()
            )
        ));

Which returns:

20 = [Tamsen Brittany:1500, Vere Hervey:1200, Maude Jaimie:1900, Clarette Cicely:1200, Tori Sheryl:1000, Rosalind Layla:1300, Quinn Tamara:1000]
40 = [Elsdon Jaycob:2000, Evonne Shari:1800]
30 = [Floyd Donny:1800, Sindy Jonie:1600, Shawn Randall:2300, Jayden Corrina:1700, Palmer Dene:2000, Addison Pam:1300, Jarrod Pace:1550, Victor Channing:1600, Osborne Shad:1100, Fraser Hewie:1100, Alvin Lance:1600]

You can also forgo the additional mapping step, and create a Map<Integer, List<Person>> instead:

Map<Integer, List<Person>> result = persons.stream()
    .collect(Collectors.groupingBy(p -> (p.getAge() / 10) * 10));
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