Bernard Rosset Bernard Rosset - 1 year ago 69
C++ Question

How to access protected method in base class from derived class?

Here is a sample of code that annoys me:

class Base {
virtual void foo() = 0;

class Derived : public Base {
Base *b; /* Initialized by constructor, not shown here
Intended to store a pointer on an instance of any derived class of Base */

virtual void foo() { /* Some implementation */ };
virtual void foo2() {
this->b->foo(); /* Compilator sets an error: 'virtual void Base::foo() is protected' */

How do you access to the protected overrided function?

Thanks for your help. :o)

Answer Source

Protected members in a base-class are only accessible by the current object.
Thus, you are allowed to call this->foo(), but you are not allowed to call this->b->foo(). This is independent of whether Derived provides an implementation for foo or not.

The reason behind this restriction is that it would otherwise be very easy to circumvent protected access. You just create a class like Derived, and suddenly you also have access to parts of other classes (like OtherDerived) that were supposed to be inaccessible to outsiders.

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