Chris Chris - 1 year ago 182
PHP Question

PHP: How to convert string duration to ISO 8601 duration format? (ie. "30 minutes" to "PT30M")

There are plenty of questions asking how to do this the other way (converting from this format), but I cant find anything on how to output in the ISO 8601 duration format in PHP.

So I have a heap of duration strings in human readable format - I want to convert them into the ISO 8601 format on the fly to print the durations for HTML5 microdata. Below is a sample of some of the strings coming in, and how they should be formatted

"1 hour 30 minutes" --> PT1H30M
"5 minutes" --> PT5M
"2 hours" --> PT2H

You get the idea.

I can push the string into an interval object in PHP:

date_interval_create_from_date_string("1 hour 30 minutes");

but there doesn't seem to be a ISO 8601 output option - how should I approach this?

Thanks all.

Answer Source

I'd convert it to a number first, then work with that.

First, use strtotime():

$time = strtotime("1 hour 30 minutes", 0);

Then you can parse it for duration, and output in PnYnMnDTnHnMnS format. I'd use the following method (inspired by

function time_to_iso8601_duration($time) {
    $units = array(
        "Y" => 365*24*3600,
        "D" =>     24*3600,
        "H" =>        3600,
        "M" =>          60,
        "S" =>           1,

    $str = "P";
    $istime = false;

    foreach ($units as $unitName => &$unit) {
        $quot  = intval($time / $unit);
        $time -= $quot * $unit;
        $unit  = $quot;
        if ($unit > 0) {
            if (!$istime && in_array($unitName, array("H", "M", "S"))) { // There may be a better way to do this
                $str .= "T";
                $istime = true;
            $str .= strval($unit) . $unitName;

    return $str;

The result:

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