M Garp - 1 year ago 91
Java Question

# product-of-other-numbers InterviewCake answer using brute force

I'm trying to answer this question using brute force so I can understand what;s going on:

https://www.interviewcake.com/question/java/product-of-other-numbers

But the problem is I don't understand why my logic is not working. Here is what I tried so far:

``````public class EveryInteger {

public static void main(String[] args) {

int a1[] = {1, 7, 3, 4};
int a2[] = new int[4];
for(int i =0; i<a1.length; i++){
int index = a1[i];
int sum = 0;

for(int j =0; j<a1.length; j++){
if(a1[i]==a1[j]){
continue;
}

sum = index * a1[j];
a2[i] = sum;
System.out.println(a2[i]);
}
}
}
``````

Can anyone please show me how you solve this problem using two for loops?

You're assigning `sum` to `a2` and printing it in the inner loop, which is incorrect. Try doing it in the outer loop instead:

``````public class EveryInteger {

public static void main(String[] args) {
int a1[] = {1, 7, 3, 4};
int a2[] = new int[4];
for(int i =0; i<a1.length; i++){
int sum = 1;

for(int j =0; j<a1.length; j++){
if(a1[i]==a1[j]){
continue;
}
sum *= a1[j];
}
a2[i] = sum;
System.out.println(a2[i]);
}
}
}
``````
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