Christopher Christopher - 1 year ago 111
Bash Question

Awk pattern always matches last record?

I'm in the process of switching from zsh to bash, and I need to produce a bash script that can remove duplicate entries in

without reordering the entries (thus no
sort -d
magic). zsh has some nice array handling shortcuts that made it easy to do this efficiently, but I'm not aware of such shortcuts in bash. I came across this answer which has gotten me 90% of the way there, but there is a small problem that I would like to understand better. It appears that when I run that awk command, the last record processed incorrectly matches the pattern.

$ awk 'BEGIN{RS=ORS=":"}!a[$0]++' <<<"aa:bb:cc:aa:bb:cc"
$ awk 'BEGIN{RS=ORS=":"}!a[$0]++' <<<"aa:bb:cc:aa:bb"
$ awk 'BEGIN{RS=ORS=":"}!a[$0]++' <<<"aa:bb:cc:aa:bb:cc:" # note trailing colon

I don't understand awk well enough to know why it behaves this way, but I have managed to work around the issue by using an intermediate array like so.

array=($(awk 'BEGIN{RS=":";ORS=" "}!a[$0]++' <<<"aa:bb:cc:aa:bb:cc:"))
# Use a subshell to avoid modifying $IFS in current context
echo $(export IFS=":"; echo "${array[*]}")

This seems like a sub-optimal solution however, so my question is: did I do something wrong in the awk command that is causing false positive matches on the final record processed?

Answer Source

The last record in your original string is cc\n which is different from cc. When unsure what's happening in any program in any language, adding some print statements is step 1 to debugging/investigating:

$ awk 'BEGIN{RS=ORS=":"} {print "<"$0">"}' <<<"aa:bb:cc:aa:bb:cc"

If you want the RS to be : or \n then just state that (with GNU awk at least):

$ awk 'BEGIN{RS="[:\n]"; ORS=":"} !a[$0]++' <<<"aa:bb:cc:aa:bb:cc"

The $ in all of the above is my prompt.

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download