Chaitanya Chaitanya - 4 months ago 14
Bash Question

Unix command to search and replace text recursively

I am looking for a UNIX command that helps me to search for a text from all the files in a folder recursively and replace it with new value. After searching in internet I came across this command which worked for me.


find ./myFolder -type f -print0 | xargs -0 sed -i 's/Application/whatever/g'


Please help me in understanding the above command. I was not able to understand this part of the command :
-print0 | xargs -0
, what this indicates? I know only basics in Unix so finding it difficulty in understanding this. I am using bash shell.

Also are there any alternate commands that provides same functionality in Unix, from google searching I got commands related to
Perl
scripting, I don't know
Perl
so dropped the idea of using it.

Answer

Also are there any alternate commands that provides same functionality in Unix

Yes you can do all this in find itself:

find ./myFolder -type f -exec sed -i 's/Application/whatever/g' '{}' \;

-exec option in find is for:

-exec utility [argument ...] ;
True if the program named utility returns a zero value as its exit status. Optional arguments may be passed to the utility. The expression must be terminated by a semicolon ('';''). If you invoke find from a shell you may need to quote the semicolon if the shell would otherwise treat it as a control operator. If the string ''{}'' appears anywhere in the utility name or the arguments it is replaced by the pathname of the current file. Utility will be executed from the directory from which find was executed. Utility and arguments are not subject to the further expansion of shell patterns and constructs.