Lucy L - 3 months ago 5x

Python Question

I am trying to make a code in Python that shows the number of steps needed to reach one from any number using a simple algorithm. This is my code:

`print('Enter the lowest and highest numbers to test.')`

min = input('Minimum number: ')

min = int(min)

max = input('Maximum number: ')

max = int(max) + 1

print(' ')

for n in range(max - min):

count = 0

num = n

while not num == 1:

if num % 2 == 0:

num = num / 2

else:

num = (num * 3) + 1

count = count + 1

print('Number: '+str(int(n)+min)+' Steps needed: '+count)

It freezes up without showing an error message, and I have no clue why this happens.

Answer

1) You are invoking `range()`

incorrectly.

Your code: `for n in range(max - min):`

produces the range of numbers starting at `0`

and ending at the value `max-min`

. Rather, you want the range of numbers starting at `min`

and ending at `max`

.

Try this:

```
for n in range(min, max):
```

2) You are performing floating-point division, but this program should use only integer division. Try this:

```
num = num // 2
```

3) You are updating the `count`

variable in the wrong loop context. Try indenting it one stop.

4) Your final line could be:

```
print('Number: '+str(n)+' Steps needed: '+str(count))
```

Program:

```
print('Enter the lowest and highest numbers to test.')
min = input('Minimum number: ')
min = int(min)
max = input('Maximum number: ')
max = int(max) + 1
print(' ')
for n in range(min, max):
count = 0
num = n
while not num == 1:
if num % 2 == 0:
num = num // 2
else:
num = (num * 3) + 1
count = count + 1
print('Number: '+str(n)+' Steps needed: '+str(count))
```

Result:

```
Enter the lowest and highest numbers to test.
Minimum number: 3
Maximum number: 5
Number: 3 Steps needed: 7
Number: 4 Steps needed: 2
Number: 5 Steps needed: 5
```

Source (Stackoverflow)

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