Hedede Hedede - 5 months ago 39
C++ Question

Why does std::stack not use template template parameter?

Why do

use type template parameter instead of template template parameter for their underlying container type?

i.e. why is
declared like this:

template<typename T, typename Container = deque<T>>
class stack;

but not like this:

template<typename T, template<typename> class Container = deque>
class stack;



Because typically containers like std::vector have more than one template argument. By not caring about it being a template, you allow every kind of container to be used.

How would

template<class T, class Allocator = std::allocator<T>> class vector;

fit onto

template<typename> class Container

as you would have it in your stack? (Hint: it doesn't!) You'd need special cases for each number of template arguments you'd want to support, which is silly, because these typically don't contribute any more information than a simple

typename Container

Note that to get at the actual template arguments of e.g. a std::vector, you have the typedefs std::vector::value_type and std::vector::allocator_type, removing the need of having these types available explicitly where you actually use the type (i.e. the Container of stack).