C. Cannon C. Cannon - 5 months ago 35
Bash Question

How to execute SED command from Makefile

So I am attempting to run a sed command from a Makefile on RaspberryPi running Raspbian. The commands I am using works perfectly when I type them directly into the terminal, but when I attempt to execute them from a Makefile I get the following feedback:

sed: -e expression #1, char 14: extra characters after command

# Quick and dirty Makefile for logsnag

CC = gcc


CFILES = myThing.c
OBJS = myThing.o


all: myThing

myThing: ${OBJS}
${CC} ${CFLAGS} ${OBJS} -o myThing

myThing.o: ${CFILES}
${CC} ${CFLAGS} myThing.c -c

install: myThing
sudo cp -f myThing/usr/local/bin
sudo cp -f ../bin/startlogging.sh /usr/local/bin
sudo cp -f ../cfg/rotateThing.cfg /etc

if [ ! -d /var/log/thingLog ]; then\
sudo mkdir /var/log/thingLog;\

sudo sed -i -e '$i touch /var/log/thingLog/thing.log /var/log/thingLog/myThing \n' /etc/rc.local;
sudo sed -i -e '$i logrotate -f /etc/rotateThing.cfg \n' /etc/rc.local;
sudo sed -i -e '$i touch /var/log/thingLog/thing.log /var/log/thingLog/myThing \n' /etc/rc.local;
sudo sed -i -e '$i /usr/local/bin/startlogging.sh > /var/log/thingLog/myThing 2>&1 & \n' /etc/rc.local;

rm -f myThing *.o


Your problem is that Makefile variable expansion looks a lot like shell variable expansion. That is, if you have a single-letter variable in a Makefile:

X=Some string

Then you refer to this variable like:


So when you have a command like this in one of your build stanzas:

sed -i -e '$i /usr/local/bin/startlogging.sh > /var/log/thingLog/myThing 2>&1 & \n'

The $i gets replaced by make (with an empty string), resulting in an invalid sed command. You can fix this by escaping the $ by doubling it:

sed -i -e '$$i /usr/local/bin/startlogging.sh > /var/log/thingLog/myThing 2>&1 & \n'

This is discussed in the Make documentation.