user2574761 user2574761 - 6 months ago 22
Python Question

How to order numeric dictionary keys with 2 digits

I have a dictionary in python like the one below, containing about 20 keys:

a = { "1": "","2":"","3":""........"20":"" }

To sort the dictionary I'm doing the following:

for key in sorted(a.iterkeys()):
print key

However it doesn't seem to keep the keys in order. It will result in this output:

1 11 12 13 14 15 16 17 18 19 2 20 3 4 5 6 7 .....

I was looking for something like:

1 2 3 4 5 6 ....

Any help would be apreciated

Answer Source

I'm assuming your real dictionary looks like this:

a = {"1": "", "2": "", …, "20": ""}

Otherwise, you wouldn't have had this problem in the first place.

If that's the problem, the answer is this:

for key in sorted(a.iterkeys(), key=int):
    print key

The trick here is that key argument. You can pass any function you want as a key to sorted (and most other sorting-related functions), and it will call that function on all of the values and sort based on the result of that function, instead of on the actual values.

The builtin int function takes any argument and (if possible) converts it to an integer. In particular, if you give it the string "3" it'll give you the number 3, and if you give it "20", it'll give you 20. And, while "3" > "20" (because strings are compared alphabetically), 3 < 20 (because numbers are compared numerically).

See the Sorting HOWTO in the docs for further details.

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