I've been trying to figure out how to determine if a double value is
. I googled the problem for a bit and found a few different approaches, however all the threads I found were at least a couple years old and seem to no longer work.
Here's what I've tried so far:
double x, y;
x = 0;
y = -0;
println(x == y);
println(Double.compare(x, y) == 0);
println(new Double(x).equals(new Double(y)));
println(Double.doubleToLongBits(x) == Double.doubleToLongBits(y));
println(Math.signum(x) == Math.signum(y));
All of those print
The reason I need to distinguish between 0 and -0, if you're wondering, is because I'm trying to parse a double value from user input, and using -0 as a sentinel value in case of an exception.