Rasmus Höglund - 1 month ago 6x

Scala Question

I want to check if two variables taken in any order can be paired into a specific pair. Basically the below, only it doesn't work because of type erasure at runtime

`def combination[A,B](x: Any, y: Any): Option[(A, B)] =`

(x, y) match {

case (a: A, b: B) => Some(a, b)

case (b: B, a: A) => Some(a, b)

case _ => None

Is there another way to do the same which would work...

Answer

Note, since it wasn't clear in your message, if you want to pattern-match against a pair of *constants* (a, b), you may want to consider back-ticks instead of what you're doing :

```
case (`a`, `b`) => Some(a, b)
```

On the other hand if you are trying to retrieve the elements of a pair of any values of type (A, B), in any order, you can do it for non-primitive types (i.e. subtypes of `AnyRef`

) :

```
import scala.reflect.ClassTag
def combination[A, B](x: AnyRef, y: AnyRef)(implicit tagA: ClassTag[A], tagB: ClassTag[B]): Option[(A, B)] = (x, y) match {
case (a: A, b: B) => Some(a, b)
case (b: B, a: A) => Some(b, a)
case _ => None
}
```

Source (Stackoverflow)

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