celllaa95 celllaa95 - 1 month ago 9
Javascript Question

How many Odd and Even number are the in a array

I have created an Array with some numbers.
I want to find out how many even, and how many odd numbers it is in
this Array. I have to print it out like this: (this is just an example)

Even number: 6

Odd number: 7

I need to make a loop that count up how many it is off even and odd numbers.

This is what I have so far

<script>

window.onload = run;

var tall = [5,10,15,20,25,30,35,40,45,50];

function run() {

tall = [5,10,15,20,25,30,35,40,45,50];

liste(tall);

}

function liste(arr) {

var sumOdd = 0; // Odd 1, 3, 5 etc..
var sumPar = 0; // Even 2, 4, 6 etc..

for(var i = 0; i < arr.length; i++) {
if(arr[i] % 2 === 0) {
sumPar += arr.length;
}
else {
sumOdd += arr.length;
} // Even numbers // Odd numbers
document.getElementById("print").innerHTML = "Partall: " + sumPar + "<br />" + "Oddetall: " + sumOdd;

}

}
}
</script>


Its something that is wrong here, and I dont know what.

Answer

You were adding arr.length which is the array length. Instead you should simply increment the number

var tall = [5, 10, 15, 20, 25, 30, 35, 40, 45, 50];

liste(tall);

function liste(arr) {
  var sumOdd = 0;
  var sumPar = 0;

  for (var i = 0; i < arr.length; i++) {
    if (arr[i] % 2 === 0) {
      sumPar++;
    } else {
      sumOdd++;
    }
  }
  
  console.log("Odd : " + sumOdd);
  console.log("Par : " + sumPar);
}

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