celllaa95 - 1 year ago 51

Javascript Question

I have created an Array with some numbers.

I want to find out how many even, and how many odd numbers it is in

this Array. I have to print it out like this: (this is just an example)

Even number: 6

Odd number: 7

I need to make a loop that count up how many it is off even and odd numbers.

This is what I have so far

`<script>`

window.onload = run;

var tall = [5,10,15,20,25,30,35,40,45,50];

function run() {

tall = [5,10,15,20,25,30,35,40,45,50];

liste(tall);

}

function liste(arr) {

var sumOdd = 0; // Odd 1, 3, 5 etc..

var sumPar = 0; // Even 2, 4, 6 etc..

for(var i = 0; i < arr.length; i++) {

if(arr[i] % 2 === 0) {

sumPar += arr.length;

}

else {

sumOdd += arr.length;

} // Even numbers // Odd numbers

document.getElementById("print").innerHTML = "Partall: " + sumPar + "<br />" + "Oddetall: " + sumOdd;

}

}

}

</script>

Its something that is wrong here, and I dont know what.

Answer Source

You were adding `arr.length`

which is the array length. Instead you should simply increment the number

```
var tall = [5, 10, 15, 20, 25, 30, 35, 40, 45, 50];
liste(tall);
function liste(arr) {
var sumOdd = 0;
var sumPar = 0;
for (var i = 0; i < arr.length; i++) {
if (arr[i] % 2 === 0) {
sumPar++;
} else {
sumOdd++;
}
}
console.log("Odd : " + sumOdd);
console.log("Par : " + sumPar);
}
```