selfsimilar selfsimilar - 7 months ago 78
PHP Question

Can I use string concatenation to define a class CONST in PHP?

I know that you can create global constants in terms of each other using string concatenation:

define('FOO', 'foo');
define('BAR', FOO.'bar');
echo BAR;


will print 'foobar'.

However, I'm getting an error trying to do the same using class constants.

class foobar {
const foo = 'foo';
const foo2 = self::foo;
const bar = self::foo.'bar';
}


foo2 is defined without issue, but declaring const bar will error out


Parse error: syntax error, unexpected '.', expecting ',' or ';'


I've also tried using functions like sprintf() but it doesn't like the left paren any more than the string concatenator '.'.

So is there any way to create class constants in terms of each other in anything more than a trivial set case like foo2?

Answer

Imho, this question deserves an answer for PHP 5.6+, thanks to @jammin comment

Since PHP 5.6 you are allowed to define a static scalar expressions for a constant:

class Foo { 
  const BAR = "baz";
  const HAZ = self::BAR . " boo\n"; 
}

Although it is not part of the question, one should be aware of the limits of the implementation. The following won't work, although it is static content (but might be manipulated at runtime):

class Foo { 
  public static $bar = "baz";
  const HAZ = self::$bar . " boo\n"; 
}
// PHP Parse error:  syntax error, unexpected '$bar' (T_VARIABLE), expecting identifier (T_STRING) or class (T_CLASS)

class Foo { 
  public static function bar () { return "baz";}
  const HAZ = self::bar() . " boo\n"; 
}
// PHP Parse error:  syntax error, unexpected '(', expecting ',' or ';'

For further information take a look at: https://wiki.php.net/rfc/const_scalar_exprs and http://php.net/manual/en/language.oop5.constants.php

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