Sagi - 4 months ago 28

C Question

I'm to stupid right now to solve this problem...

I get a BCD number (every digit is an own 4Bit representation)

For example, what I want:

- Input: 202 (hex) == 514 (dec)
- Output: BCD 0x415
- Input: 0x202
- Bit-representation: 0010 0000 0010 = 514

What have I tried:

`unsigned int uiValue = 0x202;`

unsigned int uiResult = 0;

unsigned int uiMultiplier = 1;

unsigned int uiDigit = 0;

// get the dec bcd value

while ( uiValue > 0 )

{

uiDigit= uiValue & 0x0F;

uiValue >>= 4;

uiResult += uiMultiplier * uiDigit;

uiMultiplier *= 10;

}

But I know that's very wrong this would be 202 in Bit representation and then split into 5 nibbles and then represented as decimal number again

I can solve the problem on paper but I just cant get it in a simple C-Code

Answer

You got it the wrong way round. Your code is converting from **BCD to binary**, just as your question's (original) title says. But the input and output values you provided are correct only if you convert from **binary to BCD**. In that case, try:

```
while (uiValue > 0) {
uiResult <<= 4;
uiResult |= uiValue % 10;
uiValue /= 10;
}
```

Proof: http://ideone.com/R0reQh