Kael Tee - 11 months ago 37

Python Question

I have been doing these for hours! please help! New to python

example 1990 for input year

and 2000 for end year.

basically i want the output to be

the years are 1992 1996 2000

there are 3 counts

I thought of converting them to a list and using len() but i do not know how

`#inputs`

year = int(raw_input("Input year: "))

endyear = int(raw_input("Input end year:"))

print "The number of leap years are "

counter = 0

for x in range(year,endyear+1):

if x % 4 == 0 and (x % 100 != 0 or x % 400 == 0):

counter +=1

print x

print counter

heres the current result :(

The number of leap years are

`1900`

0

1901

0

1902

0

1903

0

Answer Source

The problem was when needed year occur, the `break`

stopped your loop.

```
year = int(raw_input("Input year: "))
end_year = int(raw_input("Input end year:"))
print "The number of leap years are "
counter = 0
temp = []
for x in range(year, end_year+1):
if x % 4 == 0 and (x % 100 != 0 or x % 400 == 0):
counter +=1
temp.append(x)
print('the years are {}'.format(temp))
print('there are {} counts'.format(counter))
```

You also might want to remove brackets in *"the years are []"*, you can do that with

```
print('the years are ', ' '.join(map(str, temp)))
```