a874 a874 - 1 year ago 62
Java Question

Why the output of this java code related to polymorphism is this?

I came across this code.

class Id
public static void main(String s[])
Id obj=new Idd();
private void disp()
System.out.println("disp of parent");
class Idd extends Id
public void disp()
System.out.println("disp of child");

The output of this code is
disp of parent
. I know that
method can't be inherited in java. So at the time of function call
,compilation error should have come.

But the code successfully compiles and prints
disp of parent
. I am unable to understand why ?

Answer Source

There are two parts to this:

  1. Why did it compile?

  2. Why does it call the parent class's private disp (Id#disp) instead of the child class's public disp (Idd#disp)?

It compiled because the main function is part of the Id class, and so has access to all of the private parts of Id, including Id#disp.

It called Id#disp (the parent one) because as you said, private methods are not inherited. Polymorphism doesn't apply to them. If it did, it would be impossible for a class to have any private members. So the compiler sees obj.disp, knows that obj is typed as Id, and knows that disp is a private method of Id — so it wires it up directly, without considering any method with a matching signature on the object iself defined by a subclass. Idd#disp is not an override of Id#disp, they're entirely separate methods.

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download