Benji Kok Benji Kok - 1 year ago 117
Scala Question

Create array of literals and columns from List of Strings in Spark Sql

I am trying to define functions in Scala that take a list of strings as input, and converts them into the columns passed to the dataframe array arguments used in the code below.

val df = sc.parallelize(Array((1,1),(2,2),(3,3))).toDF("foo","bar")
val df2 = df

More specifically, I would like to create functions colFunction and litFunction (or just one function if possible) that takes a list of strings as an input parameter and can be used as follows:

val df = sc.parallelize(Array((1,1),(2,2),(3,3))).toDF("foo","bar")
val colString = List("foo","bar")
val df2 = df

I have tried mapping the colString to an Array of columns with all the transformations but this doesn't work. Any ideas on how this can be achieved? Many thanks for reading the question, and for any suggestions/solutions.

Answer Source

Just map with lit and wrap with array:

def asLitArray[T](xs: Seq[T]) = array(xs map lit: _*)

df.withColumn("an_array", asLitArray(colString)).show
// +---+---+----------+
// |foo|bar|  an_array|
// +---+---+----------+
// |  1|  1|[foo, bar]|
// |  2|  2|[foo, bar]|
// |  3|  3|[foo, bar]|
// +---+---+----------+

Regarding transformation from Seq[String] to Column of type Array this functionality is already provided by:

def array(colName: String, colNames: String*): Column 


def array(cols: Column*): Column


val cols = Seq("bar", "foo")

cols match { case x::xs =>, xs:_*)) 
// or map col: _*))

Of course all columns have to be of the same type.