Jeef Jeef - 1 year ago 119
Swift Question

Cleaner way in swift3 to read binary into a Float

I'm currently doing this:

let floatData: [UInt8] = [0x00, 0x3F, 0xC0, 0x00, 0x00, 0x66, 0x00, 0x00, 0x3F, 0xC0, 0x00, 0x00, 0x66, 0x00, 0x00, 0x3F, 0xC0, 0x00, 0x00, 0x66, 0x00]

floatData.withUnsafeBufferPointer { (bytes: UnsafeBufferPointer<UInt8>) -> Float in
let byteOffset = 1
var floatBytes : UInt32 = (UInt32(bytes[byteOffset]) << 24)
floatBytes |= (UInt32(bytes[byteOffset+1]) << 16)
floatBytes |= (UInt32(bytes[byteOffset+2]) << 8)
floatBytes |= UInt32(bytes[byteOffset+3])

return Float(bitPattern: floatBytes)

Which works fine but is a little cumbersome. I've tried casting my bytes to a
but the compiler doesn't like that.

Is there a cleaner way to extract this bit pattern that I'm missing?


Answer Source

A possible solution:

let byteOffset = 1
let result = Data(bytes: floatData[byteOffset..<byteOffset+4]).withUnsafeBytes {
    (ptr: UnsafePointer<UInt32>) in
    Float(bitPattern: UInt32(bigEndian: ptr.pointee))
print(result) // 1.5

The Data object is created from an array slice, and the closure is called with a pointer to the data. ptr.pointee dereferences the data, and UInt32(bigEndian:) converts it to host byte order.

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